5v^2+18v+15=0

Solution for 5v^2+18v+15=0 equation:

5v^2+18v+15=0

a = 5; b = 18; c = +15;
Δ = b2-4ac
Δ = 182-4·5·15
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{6}}{2*5}=\frac{-18-2\sqrt{6}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{6}}{2*5}=\frac{-18+2\sqrt{6}}{10}
$